0=x^2+95x-3000

Solution for 0=x^2+95x-3000 equation:

0=x^2+95x-3000

We move all terms to the left:

0-(x^2+95x-3000)=0

We add all the numbers together, and all the variables

-(x^2+95x-3000)=0

We get rid of parentheses

-x^2-95x+3000=0

We add all the numbers together, and all the variables

-1x^2-95x+3000=0

a = -1; b = -95; c = +3000;
Δ = b2-4ac
Δ = -952-4·(-1)·3000
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-145}{2*-1}=\frac{-50}{-2}
=+25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+145}{2*-1}=\frac{240}{-2}
=-120
$